evil twin said:
So what you are saying is that an unencumbered bullet traveling at 900 fps and weighing 230 grains has the same reaction as the reaction of the energy absorbed by the slide, the slide spring. the gun frame, your arms and body is exactly the same as the bullet hitting a target .... that 100 lbs ( 100 lbs per sq inch of energy is immediately transferred to 400 lbs per sq inch when the same 100 lbs place in a 1/4 inch dia rebar.
No, he said nothing about ENERGY. 1911 Guy specifically said "IMPACT", which is FORCE, not ENERGY. Some discussion and a few simple examples of IMPULSE, IMPACT, and FORCE here:
http://hyperphysics.phy-astr.gsu.edu/hbase/impulse.html
Note the example of the airplane and the duck. If you want to calculate the amount of FORCE transmitted by the bullet impact you need to know how long the bullet takes to decelerate once it hits the target (this is because F=MA, as Newton figured out about 400 years ago). None the less, the MOMENTUM of the duck and the airplane will be the exact same, both before and after the impact, assuming a perfectly elastic collision. Not worth going any deeper here.
You appear to be confused about energy, momentum, and pressure (PSI). They are very different things. "100 lbs per sq inch of energy" is equivalent to saying something like "100 feet per MPH of distance". It doesn't mean anything, although it contains some common units.
It's actually the MOMENTUM that is conserved.
In other words, the MOMENTUM of the slide, the slide spring, the gun frame, your arms and body is exactly the same as the MOMENTUM of the bullet when it leaves the barrel.
The MOMENTUM of the target after the bullet hits it is exactly the same as the MOMENTUM of the bullet before impact. That's why ballistic pendulums work.
Simple example and explanation of a ballistic pendulum here:
http://hyperphysics.phy-astr.gsu.edu/hbase/balpen.html
It's pretty basic physics. If you're actually interested in learning, here's a couple of examples using guns from my 1963 Schaum's Engineering Problems:
evil twin said:
that's why a man 150 lbs can lift a car 3000 lbs with little force when the moment of angle changes.
I'm not sure what a "moment of angle" is, you appear to enjoy inventing your own terminology.
But the only way a 150 pound man can lift a 3000 pound car would be if he uses at a minimum some kind of "simple machine":
https://en.wikipedia.org/wiki/Simple_machine
For example, since WORK = FORCE x DISTANCE, if he wanted to lift a 3000 pound car 1 inch by applying 150 pounds of force, he would need a lever with a ratio of 20 to 1. This means that he would have to apply a force of 150 pounds over a distance of 20 inches (150 x 20 = 3000 inch-lb) to lift the 3000 pond car 1 inch (3000 x 1 = 3000 inch-lb).