possenti
Member
I never gave it much thought, but to get the maximum distance from a fired projectile, is the optimum angle for the weapon 45 degrees? I began wondering when I was playing this online Flash game:
http://sapporo.cool.ne.jp/f1ash/flash/bowman.swf
Considering all shots are fired with the same force, and using the same projectile weight, it makes sense.
Silly question #2:
Unlike an arrow, which has tail fins to provide wind resistance - it's been said that a bullet fired straight up into the air (90 degrees) will go up and come straight down, landing on its base, because the forward inertia runs out before the stabilizing spin. Makes sense to me...
At what angle does the bullet "turn" in flight so the point impacts the ground first? Below 45 degrees?
Also - under 45 degrees, does the bullet "pitch" to match the arc of flight, or does it stay at the same angle that it left the barrel, due to the stabilizing spin? I suspect it follows the arc, since they don't leave "keyholes" in paper targets. But following the "90 degree rule", it should stay at the same angle, shoudn't it?
I'm not a physics expert, and I apologize for using layman's (or incorrect) terms. However, if anyone can figure out what the hell I'm asking, I'll do my best to understand a technical explanation.
http://sapporo.cool.ne.jp/f1ash/flash/bowman.swf
Considering all shots are fired with the same force, and using the same projectile weight, it makes sense.
Silly question #2:
Unlike an arrow, which has tail fins to provide wind resistance - it's been said that a bullet fired straight up into the air (90 degrees) will go up and come straight down, landing on its base, because the forward inertia runs out before the stabilizing spin. Makes sense to me...
At what angle does the bullet "turn" in flight so the point impacts the ground first? Below 45 degrees?
Also - under 45 degrees, does the bullet "pitch" to match the arc of flight, or does it stay at the same angle that it left the barrel, due to the stabilizing spin? I suspect it follows the arc, since they don't leave "keyholes" in paper targets. But following the "90 degree rule", it should stay at the same angle, shoudn't it?
I'm not a physics expert, and I apologize for using layman's (or incorrect) terms. However, if anyone can figure out what the hell I'm asking, I'll do my best to understand a technical explanation.