In another post I mentioned that the S&W New Departure (Safety Hammerless) had a rebounding hammer that was controlled by the mainspring tension. I spent some time looking at how it works and it just amazes me how that was engineered to work.
This started with the observation that my S&W Model One and One Half Single Action did in fact have a rebounding hammer. I studied the parts diagram looking for a piece that would make the hammer rebound and couldn't find one. Being a single action that action is very simple. It wasn't until I started to diagnose a sticking firing pin on a New Departure (Safety Hammerless) that also has a rebounding hammer that I read that the rebounding hammer is accomplished by the mainspring and its tension!
FYI - for this discussion the 1 1/2 Single Action has an exposed hammer and the New Departure has an enclosed hammer with a frame mounted, rebounding firing pin.
Basically, a properly tensioned mainspring with the correct amount of 'curve' in it drive the hammer to a point where the hammer is not only at rest, but actually imparts a decent amount of backwards force on the hammer when at rest to not only place the hammer off of the firing pin/primer but also require a significant amount of force to push it forward to contact the back primer, in the case of the Single Action, and off of the frame mounted firing pin in the New Departure.
Here are some pictures to illustrate the arrangement. These will be for the New Departure but the single action is very similar:
This is a picture of the hammer at rest
Notice the top of the hammer has backed off of the back of the firing pin. In this position the mainspring is now imparting some backwards force on the hammer. If this were a hammer mounted firing pin it would take significant force to push it back into contact with the back of the frame mounted firing pin. I can confirm this by trying it on my single action that has a hammer mounted firing pin and an exposed hammer.
It is only the weight/momentum of the hammer that 'pushes past' the at rest position and contact either the back of the firing pin (frame mounted firing pin) or the back of the primer (hammer mounted firing pin) when the trigger is pulled.
Another thing to note. Notice the curve of the mainspring in the above picture. This is showing the curve of the mainspring with the strain screw tightened fully. As the strain screw is loosened the curve of the mainspring 'flattens'. I find that the clearances between the stirrup and the relief in the hammer is so close that with the strain screw loosened the stirrup contacts the relief in the hammer and binds the action. I wish I had taken a picture of the curve of the mainspring in the cocked position but I didn't. Here is a picture of the stirrup/hammer in both the cocked and at rest position.
At Rest Position
Cocked Position
So the point of this post is the engineering that went into the design of the hammer, mainspring, stirrup to accomplish both the reliable firing of the firearm and the rebounding hammer. Today we would just model the arrangement and find out where to put the stirrup pin and how much to relieve the hammer to avoid interference between the two. But how did they engineer this back in the 1870's? The math existed, but it was complicated and not straight line. As the hammer is pulled back the curve of the mainspring changed and thus so did the place the interference would occur. And just how did they determine where the 'at rest' point was for the hammer in just the right spot so that it not only provide the energy to fire the weapon but to also provide backwards force to keep the hammer off of the firing pin/primer in the at rest position?
Inquiring minds want to know.
This started with the observation that my S&W Model One and One Half Single Action did in fact have a rebounding hammer. I studied the parts diagram looking for a piece that would make the hammer rebound and couldn't find one. Being a single action that action is very simple. It wasn't until I started to diagnose a sticking firing pin on a New Departure (Safety Hammerless) that also has a rebounding hammer that I read that the rebounding hammer is accomplished by the mainspring and its tension!
FYI - for this discussion the 1 1/2 Single Action has an exposed hammer and the New Departure has an enclosed hammer with a frame mounted, rebounding firing pin.
Basically, a properly tensioned mainspring with the correct amount of 'curve' in it drive the hammer to a point where the hammer is not only at rest, but actually imparts a decent amount of backwards force on the hammer when at rest to not only place the hammer off of the firing pin/primer but also require a significant amount of force to push it forward to contact the back primer, in the case of the Single Action, and off of the frame mounted firing pin in the New Departure.
Here are some pictures to illustrate the arrangement. These will be for the New Departure but the single action is very similar:
This is a picture of the hammer at rest
Notice the top of the hammer has backed off of the back of the firing pin. In this position the mainspring is now imparting some backwards force on the hammer. If this were a hammer mounted firing pin it would take significant force to push it back into contact with the back of the frame mounted firing pin. I can confirm this by trying it on my single action that has a hammer mounted firing pin and an exposed hammer.
It is only the weight/momentum of the hammer that 'pushes past' the at rest position and contact either the back of the firing pin (frame mounted firing pin) or the back of the primer (hammer mounted firing pin) when the trigger is pulled.
Another thing to note. Notice the curve of the mainspring in the above picture. This is showing the curve of the mainspring with the strain screw tightened fully. As the strain screw is loosened the curve of the mainspring 'flattens'. I find that the clearances between the stirrup and the relief in the hammer is so close that with the strain screw loosened the stirrup contacts the relief in the hammer and binds the action. I wish I had taken a picture of the curve of the mainspring in the cocked position but I didn't. Here is a picture of the stirrup/hammer in both the cocked and at rest position.
At Rest Position
Cocked Position
So the point of this post is the engineering that went into the design of the hammer, mainspring, stirrup to accomplish both the reliable firing of the firearm and the rebounding hammer. Today we would just model the arrangement and find out where to put the stirrup pin and how much to relieve the hammer to avoid interference between the two. But how did they engineer this back in the 1870's? The math existed, but it was complicated and not straight line. As the hammer is pulled back the curve of the mainspring changed and thus so did the place the interference would occur. And just how did they determine where the 'at rest' point was for the hammer in just the right spot so that it not only provide the energy to fire the weapon but to also provide backwards force to keep the hammer off of the firing pin/primer in the at rest position?
Inquiring minds want to know.
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