anymanusa
Member
I don't think you understand the laws of physics...
A human body doesn't behave as a rigid object and if it did, firing a shot on a frictionless surface, could very possibly produce a 2" movement in the opposite direction of the bullet, for a 180lb. subject. The equations are pretty simple, let me see if I can remember them,... yes it is m1*v1=m2*v2. M=mass, V=Velocity, 1 for the bullet mass and velocity, and 2 for the shooter mass, and velocity to be solved for.
This equation would yeild the recoil velocity of the shooter, given that the 'shooter' behave like a solid rigid object. The movement of the shooter and the bullet would be indefinite, if friction was excluded, but alas, we live in the real world, and 2" doesn't seem like a stretch to me.
Any bullet from a .308 that expanded so fiercely inside of a watermellon as to not punch through it but move inches back.. has my full respect.
.Have these people ever heard of Newtons Laws.
To push an 18 pound melon, from rest back 20 inches would mean that a 180 pound shooters entire body will be shoved back at least 2 inches
A human body doesn't behave as a rigid object and if it did, firing a shot on a frictionless surface, could very possibly produce a 2" movement in the opposite direction of the bullet, for a 180lb. subject. The equations are pretty simple, let me see if I can remember them,... yes it is m1*v1=m2*v2. M=mass, V=Velocity, 1 for the bullet mass and velocity, and 2 for the shooter mass, and velocity to be solved for.
This equation would yeild the recoil velocity of the shooter, given that the 'shooter' behave like a solid rigid object. The movement of the shooter and the bullet would be indefinite, if friction was excluded, but alas, we live in the real world, and 2" doesn't seem like a stretch to me.
Any bullet from a .308 that expanded so fiercely inside of a watermellon as to not punch through it but move inches back.. has my full respect.