Why guess? I'm waiting for you to do some more math!
I'm afraid that without knowing the physical properties of the polymer frame, or the required numbers from it, I'm stuck guessing. But you knew that already, didn't ya?
Then again, I'm seriously considering just buying another Glock, removing the trigger safety, and doing some drop testing.....
It'd be much more educational, I think, than page upon page of mathematic formulas. Probably a lot more fun too.
Besides, I don't see you generating any real "proof" of your side of the argument.
( This last part really is meant as a joke. I don't think any of this is going to prove a damn thing other than that some of us have entirely too much time on our hands.
)
Here's something to think about while you're working out the numbers. The striker is a relatively small light part--very roughly comparable in weight to the trigger assembly. Yet Glock felt the need to put a drop safety on the striker and you tacitly acknowledge the wisdom of this feature. Presumably that says that Glock designers felt that it was possible for the gun to be dropped in such a fashion that the striker could not only move forward, but could move forward with enough force to "pop" the primer.
It would seem reasonable that if (in the absence of the proper safeties) the striker can develop enough energy from a drop to actually fire the gun that the trigger might also move around a surprising amount from the same kind of deceleration forces. Ok, that's as close to guessing as I'm gonna get.
A relatively small light part that's already partially spring-loaded in the general direction of the primer....
I don't know if the trigger bar could be jarred out of position and "drop" the striker or not, but if it did manage to "get lose" from the trigger bar, either because of a worn sear or the sear breaking, it'd have the extra energy of the partially compressed striker spring to add to the momentum of the fall. And that might very well be enough to set a round off. And without the trigger having to move at all, as well.
As far as the striker possibly setting a cartridge off from the unset position.... I wanna know how you got a live round in the chamber without setting the striker.
Or was it a dud you forgot to clear? ( Hehehe... hey boys, there's you "second strike capability".
)
Oh and one other thing.... something I should have though about earlier.... How are you gonna drop our hypothetical Glock on it's butt so that it lands on it's center of mass/center of gravity, and
not have the slide jarred out of battery?
I've been looking at a pic of a G19, and honestly, short of dropping it on some sort of projection, I can't figure out how to get it to land so that the forces line up in the right direction, or don't get bled off by rotation... ( The butt on all Glock models stick out at least a little past the rear of the slide. )
The best I can come up with is for it to land on the back corner of the slide. And even at that it's going to require much more force because of the angle. Also, the amount of ammo left (or not) in the mag is going to change the balance so that it may just rotate and bleed away the energy anyway.
Here, here's a pic... take a look and see what you think:
The Black line at the bottom represents a flat hard surface.
The Red arrow is the the direction that force is required in to move the trigger.
The Yellow spot indicates the first point of impact if dropped "flat".
The Blue and green spots indicate the second/third points of impact, when the gun "rolls" off the primary impact point.
The Yellow arrow on the muzzle indicates the direction of rotation at impact.
The Green arrow indicates the secondary direction of force. It's also pretty close to the direction of force should the gun be dropped with the back edge of the slide landing first.
I didn't bother indicating a center of mass, since that varies with the amount of ammunition in the magazine.
So how 'bout it John? How are we gonna drop this thing so it'll go "Bang!"?
J.C.